y^2+2y-1155=0

Solution for y^2+2y-1155=0 equation:

y^2+2y-1155=0

a = 1; b = 2; c = -1155;
Δ = b2-4ac
Δ = 22-4·1·(-1155)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-68}{2*1}=\frac{-70}{2}
=-35
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+68}{2*1}=\frac{66}{2}
=33
$